In the diagram, 0 is the centre of the circle. Find the value x
34
29
17
14
Correct answer is D
POQ in a straight line
Hence, < POQ + < QOR = 180o
56o + < QOR = 180o
< QOR = 180o - 56o
= 124o
Now, in \(\bigtriangleup\) QOR OR = OQ = Radius
< ORQ = < OQR = 2x (Base angles of an Isosceles \(\bigtriangleup\))
2x + 124 + 2x = 180o
4x + 124 = 180
4x = 180 - 124
4x = 56
x = \(\frac{56}{4}\)
x = 14o