If g(x) = √(1-x\(^2\)), find the domain of g(x)
x < -1 or x > 1
x ≤ -1 or x ≥1
-1 ≤ x ≤ 1
-1 < x < 1
Correct answer is C
1 - x\(^2\) ≥ 0
-x\(^2\) ≥ -1
x\(^2\) ≤ 1
√x\(^2\) ≤ 1
|x| ≤ 1
-1 ≤ x ≤ 1
| Distance(km) | 3 | 4 | 5 | 6 | 7 | 8 |
| Frequency | 5 | 4 | x | 9 | 2x | 1 |
5
6
7
8
Correct answer is C
7km has the highest frequency(14)
The table shows the distribution of the distance (in km) covered by 40 hunters while hunting.
| Distance(km) | 3 | 4 | 5 | 6 | 7 | 8 |
| Frequency | 5 | 4 | x | 9 | 2x | 1 |
If a hunter is selected at random, find the probability that the hunter covered at least 6km.
\(\frac{3}{5}\)
\(\frac{2}{5}\)
\(\frac{3}{8}\)
\(\frac{9}{40}\)
Correct answer is A
5+4+x+9+2x+1 = 40
19+3x = 40
3x = 21
x = 7
| Distance(km) | 3 | 4 | 5 | 6 | 7 | 8 |
| Frequency | 5 | 4 | 7 | 9 | 14 | 1 |
The probability that the hunter covered at least 6km, means the hunter covered either 6km or 7km, or 8km.
24 hunters covered at least 6km
| 24
40 |
= | 3
5 |
If →PQ = -2i + 5j and →RQ = -i - 7j, find →PR
-3i + 12j
-3i - 12j
-i + 12j
i - 12j
Correct answer is C
→PQ = →PR + →RQ
→PR = →PQ - →RQ
→PR = -2i + 5j - (-i - 7j)
→PR = -2i + 5j + i + 7j
→PR = -i + 12j.
(10 units, 053º)
(9 units, 049º)
(10 units, 037º)
(9 units, 027º)
Correct answer is A
|→PQ| = √[(2-(-4))\(^2\) + (3-(-5))\(^2\)]
|→PQ| = √\(6^2 + 8^2\)
|→PQ| = √100
|→PQ| = 10units
tanθ = \(\frac{3--5}{2--4}\)
tanθ = \(\frac{4}{3}\)
θ = \(tan^{-1}\frac{4}{3}\)
= 53º