Given that P = (-4, -5) and Q = (2,3), express →PQ in the form (k,θ). where k is the magnitude and θ the bearing.
(10 units, 053º)
(9 units, 049º)
(10 units, 037º)
(9 units, 027º)
Correct answer is A
|→PQ| = √[(2-(-4))\(^2\) + (3-(-5))\(^2\)]
|→PQ| = √\(6^2 + 8^2\)
|→PQ| = √100
|→PQ| = 10units
tanθ = \(\frac{3--5}{2--4}\)
tanθ = \(\frac{4}{3}\)
θ = \(tan^{-1}\frac{4}{3}\)
= 53º