x < -1 or x > 1
x ≤ -1 or x ≥1
-1 ≤ x ≤ 1
-1 < x < 1
Correct answer is C
1 - x2 ≥ 0
-x2 ≥ -1
x2 ≤ 1
√x2 ≤ 1
|x| ≤ 1
-1 ≤ x ≤ 1
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