x < -1 or x > 1
x ≤ -1 or x ≥1
-1 ≤ x ≤ 1
-1 < x < 1
Correct answer is C
1 - x\(^2\) ≥ 0 -x\(^2\) ≥ -1 x\(^2\) ≤ 1 √x\(^2\) ≤ 1 |x| ≤ 1 -1 ≤ x ≤ 1
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