From the diagram above, Find the value of < ROP
110o
70o
95o
85o
Correct answer is C
< ROP = 95o (Exterior angle of cyclic quadrilateral)
In the diagram above, l1 is parallel to l2, Find the value of < PMT
82o
36o
72o
118o
Correct answer is A
< MPT = 180o - 118o = 62o
< PML = 62o ( Alternative angle)
y + 2y + 10o + 62o = 180o (Angles on a straight line)
3y = 180 - 72
\(\frac{3y}{3}\) = \(\frac{108}{3}\)
y = 36o
< PMT = 2y + 10 = 2(36) + 10 = 82o
5
7
6
8
Correct answer is D
\(\frac{(n - 2) 180}{180}\) = \(\frac{1080}{180}\)
(n - 2) = 6
n = 6 + 2 = 8
From the diagram above, find the value of < OTQ
230o
55o
115o
65o
Correct answer is D
< OTQ = \(\frac{130}{2}\)
= 65o
2
\(\frac{3}{2}\)
\(\frac{2}{3}\)
3
Correct answer is B
T2 = \(\frac{8}{9}\), T6 = 4\(\frac{1}{2}\)
ar = \(\frac{8}{9}\)
ar5 = \(\frac{9}{2}\)
\(\frac{ar}{ar^5}\) = \(\frac{8}{9}\) x \(\frac{2}{9}\)
\(\frac{1}{r^4}\) = \(\frac{16}{81}\)
r = \(\sqrt[4]{18/16}\) = \(\frac{3}{2}\)
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