The area of a circle of radius 4cm is equal to (Take π = 3.142 )
10.3cm2
15.7cm2
50.3cm2
17.4cm2
Correct answer is C
Area of a circle (A) = πr2
Radius = 4cm
π = 3.142
A = 3.142 × (4)2
= 3.142 × 16
= 50.272
A = 50.3cm2 (1dp)
2x/(x + 1)(x−3)
2x/(x + 1)(x−1)
2x/(x + 1)2
2x(x+1)2
Correct answer is B
[1 ÷ (x+1)] + [1 ÷ (x − 1)]
= ((x − 1) + [(x + 1)) ÷ (x+1)(x − 1)]
Using the L.C.M.
= (x − 1 + x + 1) ÷ (x + 1)(x − 1)
= (x + 2 − 1 + 1) ÷ (x + 1)(x − 1)
= 2x ÷ (x + 1)(x − 1) =2x ÷ (x + 1)(x − 1)
17.1cm2
27.2cm2
47.1cm2
37.3cm2
Correct answer is C
Find the slant height
l2=h2+r2(h=4cm,r=3cm)
l2=42+32=16+9=25
l2=√25
Squaring both sides
l = 5cm
The area of curved surface (s) =π(3)(5)
15π = 15 × 3.14
= 47.1cm2
5x44+7x33+2x+C
5x44+7x33−x2+5x+C
5x33+7x2x−x+C
2x23+x5−C
Correct answer is B
∫(5x3+7x2−2x+5)dx
= 5x44+7x33−2x22+5x+c
= 5x44+7x33−x2+5x+c
2 log5y + 5log5 y2 − 3
log5 y2 + 5log5 x + 3
25logy 5 + 3
2log5y + 5log5x − ½ log5b −3
Correct answer is D
log5(y2x5÷125b12)
= log5y2+log5x5−[log5125+log5b12
= 2log5y+5log5x−log553−12log5b
= 2log5y+5log5x−3−12log5b