2 log5y + 5log5 y2 − 3
log5 y2 + 5log5 x + 3
25logy 5 + 3
2log5y + 5log5x − ½ log5b −3
Correct answer is D
\log_{5}(y^{2} x^{5} \div 125b^{\frac{1}{2}})
= \log_{5} y^{2} + \log_{5} x^{5} - [\log_{5} 125 + \log_{5} b^{\frac{1}{2}}
= 2\log_{5} y + 5\log_{5} x - \log_{5} 5^{3} - \frac{1}{2} \log_{5} b
= 2\log_{5} y + 5\log_{5} x - 3 - \frac{1}{2}\log_{5} b
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