5x44+7x33+2x+C
5x44+7x33−x2+5x+C
5x33+7x2x−x+C
2x23+x5−C
Correct answer is B
∫(5x3+7x2−2x+5)dx
= 5x44+7x33−2x22+5x+c
= 5x44+7x33−x2+5x+c
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