180
60
25
20
Correct answer is D
Let x rep. numbers of boys that can work at \(\frac{5}{4}\) the rate at
which the 10 girls work
For 1 hrs, x boys will work for \(\frac{\frac{1}{5} \times 10}{4}\)
x = \(\frac{5}{4}\) x 10
= 8 boys
8 boys will do the work of ten girls at the same rate
4 + 8 = 12 bous cut the field in 5 hrs for 3 hrs,
\(\frac{12 \times 5}{3}\) boys will be needed = 20 boys.
0
0.9
1.1
1.2
Correct answer is C
\(\frac{0.021741 \times 1.2047}{0.023789}\) = \(\frac{0.0255 \times 1.2}{0.024}\) (to 216)
= \(\frac{0.0264}{0.024}\) = 1.1
x < 11
x < -1
x > 6
x > 11
Correct answer is D
\(\frac{1}{3}\) (x + 1) - 1 > \(\frac{1}{5}\)(x + 4) = \(\frac{x + 1}{3} - 1\) > \(\frac{x + 4}{5}\)
\(\frac{x + 1}{3} - \frac{x + 4}{5} -1\) > 0
= \(\frac{5x + 5 - 3x - 12}{15}\)
2x - 7 > 15
2x > 22 = x > 11
Find all median of the numbers 89, 141, 130, 161, 120, 131, 131, 100, 108 and 119
131
125
123
120
Correct answer is B
Arrange in ascending order
89, 100, 108, 119, 120,130, 131, 131, 141, 161
Median = \(\frac{120 + 130}{2}\) = 125
Evaluate (212)\(_3\) - (121)\(_3\) + (222)\(_3\)
(313)\(_3\)
(1000)\(_3\)
(1020)\(_3\)
(1222)\(_3\)
Correct answer is C
Evaluate (212)\(_3\) - (121)\(_3\) + (222)\(_3\)
(212)\(_3\) + (222)\(_3\) = 1211\(_3\)
→ 1211\(_3\) - 121\(_3\)
= 1020\(_3\)