Find the value of x for \(\frac{2 + 2x}{3} - 2 \geq \frac{4x - 6}{5}\)

A.

x \(\geq\) -5

B.

x \(\geq\) -1

C.

x \(\leq\) -1

D.

x \(\leq\) 3

Correct answer is C

\(\frac{2 + 2x}{3} - 2 \geq \frac{4x - 6}{5}\)

\(\frac{2 + 2x - 6}{3} \geq \frac{4x - 6}{5}\)

\(\frac{2x - 4}{3} \geq \frac{4x - 6}{5}\)

\(5(2x - 4) \geq 3(4x - 6)\)

\(10x - 20 \geq 12x - 18\)

\(10x - 12x \geq -18 + 20\)

\(-2x \geq 2\)

\(x \leq -1\)