0.3010
0.4771
0.6532
0.9542
Correct answer is C
log\(_{10}\)2 = 0.3010 and log\(_{10}\)3 = 04771
log\(_{10} 4.5 = log_{10}\) (\(\frac{3 \times 3}{2}\))
log\(_{10}\) 3 + log\(_{10}\) 3 - log\(_{10}\)2 = 0.4471 + 0.771 - 0.3010
= 0.6532
18
15
10
5
Correct answer is D
No of students offering physics are
\(\frac{12}{360}\) x 150 = 5
The goals scored by 40 football teams from three league divisions are recorded below
| No of goals | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
| Frequency | 4 | 3 | 15 | 16 | 1 | 0 | 1 |
What is the total number of goals scored by all the teams?
21
40
91
96
Correct answer is C
Let x represent number of goals \(\begin{array}{c|c|} x & F & Frequency(fx)\\\hline 0 & 4 & 0 \\\hline 1 & 3 & 3\\\hline 2 & 15 & 30 \\\hline 3 & 16 & 48\\ \hline 4 & 1 & 4 \\\hline 5 & 0 & 0 \\\hline 6 & 1 & 6 \\\hline & \sum Fx = 91& \end{array}\)
\(\sum fx\) = 91
\(\frac{15}{17}\)
\(\frac{8}{17}\)
\(\frac{8}{15}\)
\(\frac{12}{17}\)
Correct answer is A
ABCD is the floor. By pathagoras
AC\(^2\) = 144 + 81 = \(\sqrt{225}\)
AC = 15cm
Height of room 8m, diagonal of floor is 15m
Therefore, the cosine of the angle which a diagonal of the room makes with the floor is
EC\(^2\) = 15\(^2\) + 8\(^2\) cosine
\(\frac{adj}{Hyp} = \frac{15}{17}\)
EC\(^2\) = \(\sqrt{225 + 64}\)
EC = \(\sqrt{289}\)
= 17
What is the circumference of latitude 0\(^o\)S if R is the radius of the earth?
cos \(\theta\)
2\(\pi\)R cos \(\theta\)
R sin \(\theta\)
2 \(\pi\) r sin \(\theta\)
Correct answer is B
Circumstances of latitude 0\(^o\)s where R is the radius of the earth 2\(\pi\)r cos \(\theta\)