If y = 8x\(^3\) - 3x\(^2\) + 7x - 1, find \(\frac{\mathrm d^2 y}{\mathrm d x^2}\).

A.

48x - 6

B.

11x\(^2\) + 6x - 7

C.

32x + 7

D.

24x\(^2\) - 6x + 7

Correct answer is A

y = 8x\(^3\) - 3x\(^2\) + 7x - 1

\(\frac{\mathrm d^2 y}{\mathrm d x^2}  = \frac{\mathrm d}{\mathrm d x} (\frac{\mathrm d y}{\mathrm d x})\)

= \(\frac{\mathrm d}{\mathrm d x} (24x^2 - 6x + 7)\)

\(\frac{\mathrm d^2 y}{\mathrm d x^2} = 48x - 6\)