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Given the matrix \(A = \begin{vmatrix} 3 & -2 \\ 1 &...

Given the matrix A=|3216|. Find the inverse of matrix A.

A.

|6216|

B.

|211112320110|

C.

|3216|

D.

|310110120320|

Correct answer is D

A=|3216|

|A| = (3 x 6) - (-2 x 1)

= 18 + 2

= 20.

A1 = 120|6213|

= |620220120320|

= |310110120320|