Factorize completely the expression abx2+6y−3ax−2byx
(ax - 2y)(bx - 3)
(bx + 3)(2y - ax)
(bx + 3)(ax - 2y)
(ax - 2y)(ax - b)
Correct answer is A
abx2+6y−3ax−2byx
Collecting like terms, we have
abx2−3ax+6y−2byx
= ax(bx−3)+2y(3−bx)
= ax(bx−3)−2y(bx−3)
= (ax−2y)(bx−3)
The graph of f(x) = x2 - 5x + 6 crosses the x-axis at the points
(-6, 0), (-1, 0)
(-3, 0), (-2,0)
(-6, 0),(1, 0)
(2, 0), (3, 0)
Correct answer is D
When X = 3, Y = 0(3, 0),
When x = 2, y = 0(2, 0)
1
2
3
4
Correct answer is B
x - p,x = p
2p2 - p2 + p = 6
= p2 + p - 6
= 0
p = 3, 2
If x - 1 and x + 1 are both factors of the equation x3 + px2 + qx + 6 = 0, evaluate p and q
-6, -1
6, 1
1, -1
6, -6
Correct answer is A
x3+px2+qx+6=0
f(x - 1) = 0; f(1) = 0.
13+p(12)+q(1)+6=0⟹p+q=−7...(1)
f(x + 1) = 0; f(-1) = 0.
(−1)3+p(−12)+q(−1)+6=0⟹p−q=−5...(2)
Subtract (2) from (1).
2q=−2⟹q=−1
p−(−1)=−5⟹p=−5−1=−6
(p,q)=(−6,−1)
If S = (x : x2 = 9, x > 4), then S is equal to
4
{0}
∅
{∅}
Correct answer is C
No explanation has been provided for this answer.