Factorize completely the expression \(abx^2 + 6y - 3ax - 2byx\)
(ax - 2y)(bx - 3)
(bx + 3)(2y - ax)
(bx + 3)(ax - 2y)
(ax - 2y)(ax - b)
Correct answer is A
\(abx^{2} + 6y - 3ax - 2byx\)
Collecting like terms, we have
\(abx^{2} - 3ax + 6y - 2byx\)
= \(ax(bx - 3) + 2y(3 - bx)\)
= \(ax(bx - 3) - 2y(bx - 3)\)
= \((ax - 2y)(bx - 3)\)
The graph of f(x) = x2 - 5x + 6 crosses the x-axis at the points
(-6, 0), (-1, 0)
(-3, 0), (-2,0)
(-6, 0),(1, 0)
(2, 0), (3, 0)
Correct answer is D
When X = 3, Y = 0(3, 0),
When x = 2, y = 0(2, 0)
1
2
3
4
Correct answer is B
x - p,x = p
2p2 - p2 + p = 6
= p2 + p - 6
= 0
p = 3, 2
-6, -1
6, 1
1, -1
6, -6
Correct answer is A
\(x^{3} + px^{2} + qx + 6 = 0\)
f(x - 1) = 0; f(1) = 0.
\(1^{3} + p(1^{2}) + q(1) + 6 = 0 \implies p + q = -7 ... (1)\)
f(x + 1) = 0; f(-1) = 0.
\((-1)^{3} + p(-1^{2}) + q(-1) + 6 = 0 \implies p - q = -5 ... (2)\)
Subtract (2) from (1).
\(2q = -2 \implies q = -1\)
\(p - (-1) = -5 \implies p = -5 - 1 = -6\)
\((p, q) = (-6, -1)\)
If S = (x : x\(^2\) = 9, x > 4), then S is equal to
4
{0}
\(\emptyset\)
{\(\emptyset\)}
Correct answer is C
No explanation has been provided for this answer.