(ax - 2y)(bx - 3)
(bx + 3)(2y - ax)
(bx + 3)(ax - 2y)
(ax - 2y)(ax - b)
Correct answer is A
abx2+6y−3ax−2byx
Collecting like terms, we have
abx2−3ax+6y−2byx
= ax(bx−3)+2y(3−bx)
= ax(bx−3)−2y(bx−3)
= (ax−2y)(bx−3)
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