-6, -1
6, 1
1, -1
6, -6
Correct answer is A
x3+px2+qx+6=0
f(x - 1) = 0; f(1) = 0.
13+p(12)+q(1)+6=0⟹p+q=−7...(1)
f(x + 1) = 0; f(-1) = 0.
(−1)3+p(−12)+q(−1)+6=0⟹p−q=−5...(2)
Subtract (2) from (1).
2q=−2⟹q=−1
p−(−1)=−5⟹p=−5−1=−6
(p,q)=(−6,−1)
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