i only
ii only
iii only
ii and iii only
i,ii and iii
Correct answer is B
No explanation has been provided for this answer.
14.4\(\Omega\)
28.8\(\Omega\)
144\(\Omega\)
288\(\Omega\)
2880\(\Omega\)
Correct answer is B
Heat energy = Electrical energy
6 x 105 = \(\frac{V^2}{R}\)t
R = \(\frac{240 \times 240 \times 5 \times 60}{6 \times 105}\)
= 28.8\(\Omega\)
8 : 1
4 : 1
2 : 1
1 : 1
1 : 4
Correct answer is C
Resistance \(\alpha\) \(\frac{length}{area}\)
\(\frac{R_Q}{R_P}\) = \(\frac{L_QA_P}{L_PA_Q}\)
LQ = 2LP
DQ = 2DP
AP = \(\pi\)\(\frac{(2D_P)^2}{2}\)
= \(\pi\)DP
AQ = \(\pi\)\(\frac{(D_P)^2}{2}\)
= \(\frac{1}{4}\)\(\pi\)DP
therefore, \(\frac{R_Q}{R_P}\) = \(\frac{2L_P \times \pi D_P}{L_P \times \frac{1}{4} \pi D_P}\)
= 2 : 1
Which of the following will convert a milliammeter to a voltmeter?
low series resistance
low parallel resistance
high series resistance
high parallel resistance
parallel resistance equal to milliammeter resistance
Correct answer is C
No explanation has been provided for this answer.
0.05\(\Omega\)
1.00\(\Omega\)
1.50\(\Omega\)
2.00\(\Omega\)
2.50\(\Omega\)
Correct answer is D
The E.M.F of a circuit is given by
\(E=I(R+r)\)
Hence, E = 0.15(8+r) = 0.3(3+r)
1.2 + 0.15r = 0.9 + 0.3r
1.2 - 0.9 = 0.3r - 0.15r
0.3 = 0.15r
r = \(\frac{0.3}{0.15}\)
r = 2\(\Omega\)