An electric kettle, connected to a 240V mains, produces 6.0 x 10⁵J of heat energy to boil a quantity of water in 5 minutes. Find the resistance of the kettle.

14.4\(\Omega\)

28.8\(\Omega\)

144\(\Omega\)

288\(\Omega\)

2880\(\Omega\)

Correct answer is B

Heat energy = Electrical energy

6 x 10⁵ = \(\frac{V^2}{R}\)t

R = \(\frac{240 \times 240 \times 5 \times 60}{6 \times 105}\)

= 28.8\(\Omega\)

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An electric kettle, connected to a 240V mains, produces 6.0 x 105J of heat energy to boil a quantity of water in 5 minutes. Find the resistance of the kettle.