\(\frac{3}{5}\)
\(\frac{2}{5}\)
\(\frac{4}{5}\)
\(\frac{1}{5}\)
Correct answer is A
A rectangle, a square and a rhombus are the only parallelogram
∴ Probability of a parallelogram = \(\frac{3}{5}\)
40
38
33
3
Correct answer is B
CF (6) = 5 + 6 + 8 + 10 + 6 + 3
= 38
18
17\(\frac{1}{2}\)
16
15
Correct answer is D
Re-arranging them 2, 3, 5, 7, 8, 9, 12, 14
Mean = P and median = Q
P = \(\frac{2 + 2 + 5 + 7 + 8 + 9 + 12 + 14}{8}\)
\(\frac{60}{8}\) = 7.5
median (Q) = \(\frac{7 + 8}{2}\)
\(\frac{15}{2}\) = 7.5
P + Q = 7.5 + 7.5 = 15
21
40
91
96
Correct answer is C
Let x rep. number of goals
\(\begin{array}{c|c} "f & " & frequency\\\hline x & f & fx\\ 0 & 4 & 0\\1 & 3 & 3\\2 & 15 & 30\\3 & 16 & 48\\4 & 1 & 4\\5 & 0 & 0 \\ 6 & 1 & 6\end{array}\)
\(\sum fx\) = 91
Total number of goals scored is \(\sum fx\)= 91
187o30'
172o30'
135o225o
202o30' 157o 30'
Correct answer is D
Period of day light is from 5.30 to 7.00p.m - 13hrs 30min. interval
24hrs make 1 day
∴ period of darkness = 24hrs - 13hrs 30mins = 10hrs 30mins.
Angle of sector of daylight = \(\frac{13 \times 60 + 30 \times 360}{(24 \times 60)}\)
= \(\frac{810}{1440}\) x 360o
= \(\frac{291600}{1440}\)
= 202.5o
202.5o = 202.30o
darkness period = 360o - 202o 30'
= 157o30'
= 202o30' 157o 30'