If a u2 - 3v2 and b = 2uv + v2 evaluate (2a - b)(a - b2), when u = 1 and v = -1

A.

9

B.

15

C.

27

D.

33

View answer & explanation

Correct answer is A

a = u2 - 3y2 = (1)2 - 3(-1) = -2

b = 2uu + v2 + v2

= 2(1)(-1) + (-1)2 = -1

∴ 2(2a - b)(a - b∴) = [2(-2) - 1](-2 - (-1)2)

= -3 - 3

= 9

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