\(\frac{3}{2}\)
\(\frac{1}{3}\)
3
\(\frac{2}{3}\)
Correct answer is D
If P = \(\frac{2}{3}\) (\(\frac{1 - r^2}{n^2}\)), find n when r = \(\frac{1}{3}\) and p = 1
p = \(\frac{2(1 - r^2)}{3n^2}\) when r = \(\frac{1}{3}\) and p = 1
1 = \(\frac{2}{3}\) \(\frac{(1 - (\frac{1}{3})^2)}{n^2}\)
n2 = \(\frac{2(3 - 1)}{3 \times 3}\)
n2 = \(\frac{2 \times 2}{3 \times 3}\)
= \(\frac{4}{9}\)
n = \(\frac{4}{9}\)
= \(\frac{2}{3}\)