In the figure, QRST is a rectangle; PT// QM, angle P = 60o. Find angle MUR
150o
30o
60o
120o
90o
Correct answer is A
QRST is a rectangle
PT //QM, P = 60o = angle MUR = 150o
10cm
12.5cm
8cm
6cm
5cm
Correct answer is E
Area of a //gm PQRS = B X H Area of a //gm PQRS = PQ x TF 50 = 10TF TF = 5cm
If K is a constant, which of the following equations best describes the parabola?
y = kx2
x = y2 - k
y = k - x2
x2 = y2 - k
y = (k - x)2
Correct answer is B
The parabola is best described by the equation x = y2 - k because all other equations do not give the equation of the parabola in this position. C for example is the equation of a hyperbola facing downwards. D is the equation of a hyperbola A and E are equations of parabola facing upwards
In the fiqure where PQRTU is a circle, ISTI = IRSI and angle TSR = 52o. Find the angle marked m
128o
52o
104o
64o
116o
Correct answer is E
< STR = \(\frac{180 - 52}{2}\) = \(\frac{128}{2}\) = 64o
< PTR = 180 - < STR(angle on a straight line)
= 180 - 64 = 116o
< PQR + < PTR = 180(Supplementary)
< PQR + 118 = 180
< PQR = 180 - 118
= 64
M = 180 - < PQR
= 180 - < PQR = 180 - 64
= 116o
155km/hr
50km/hr
40km/hr
124km/hr
84km/hr
Correct answer is E
Distance = 155 - 50 = 105km
Time = 75mins
= \(\frac{75}{60}\)hr = \(\frac{5}{4}\)hr
Average speed = \(\frac{Distance}{time}\) = \(\frac{105}{\frac{5}{4}}\)
= \(\frac{105 \times 4}{5}\)
= 84km\h
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