In the parallelogram PQRS, PE is perpendicular to QR. Fin...
In the parallelogram PQRS, PE is perpendicular to QR. Find the area of the parallelogram.
60cm2
65cm2
72cm2
132cm2
156cm2
Correct answer is D
By Pythagoras, PE\(^2\) = 12\(^2\) - 5\(^2\)
= 144 - 25 = 119
h = PE\(^2\) = √119 = 10.9 ≈ 11cm,
Area of 11gm = b x h
QR = b =(5 + 7)cm = 12cm
area = 12 x 11
= 132cm\(^2\)
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