k = 5, r = -1
k = 5, r = 2
k = 2, r = -5
k = -1, r = 5
Correct answer is B
\(x^{2} + 4x + k = (x + r)^{2} + 1\)
\(x^{2} + 4x + k = x^{2} + 2rx + r^{2} + 1\)
Comparing the LHS and RHS equations, we have
\(2r = 4 \implies r = 2\)
\(k = r^{2} + 1 = 2^{2} + 1 = 5\)
Which of the following is not an equation of a circle? ...
Find \(\int \frac{x^{3} + 5x + 1}{x^{3}} \mathrm {d} x\)...
In △PQR, \(\overline{PQ}\) = 5i - 2j and \(\overline{QR}\) = 4i + 3j. Find \(\...
Two forces, each of magnitude 16 N, are inclined to each other at an angle of 60°. Calculate the...
Find the coefficient of the \(6^{th}term\) in the binomial expansion of \((1 - \frac{2x}{3})10\...