x+3x−2,x≠2
x−3x+2,x≠−2
3x−2x+1,x≠−1
3x+2x−1,x≠1
Correct answer is D
f:x→x+2x−3,x≠3,f=?
Let f:x=y
y=x+2x−3
=x+2=y(x−3)
=x−xy=−3y−2
=x(1−y)=−3y−2
=x=−3y−21−y=−(3y+2)−(y−1)
=x=3y+2y−1
∴f ^{-1} : x=\frac{3x + 2}{x - 1},x ≠ 1
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