(-2, 10)
(-2, 2)
(-2, -2)
(-2, -6)
Correct answer is D
\(y = x^{2} + 4x - 2\)
\(\frac{\mathrm d y}{\mathrm d x} = 2x + 4 = 0\)
\(2x = -4 \implies x = -2\)
\(y(-2) = (-2^{2}) + 4(-2) - 2 = 4 - 8 - 2 = -6\)
\(\therefore (x, y) = (-2, -6)\)
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