| Face | 1 | 2 | 3 | 4 | 5 | 6 |
| Frequency | 12 | 18 | y | 30 | 2y | 45 |
Given the table above as the results of tossing a fair die 150 times. Find the probability of obtaining a 5.
\(\frac{1}{10}\)
\(\frac{1}{6}\)
\(\frac{1}{5}\)
\(\frac{3}{10}\)
Correct answer is C
Probability of obtaining a 5 = \(\frac{\text{frequency of 5}}{\text{total frequency}}\)
\(12+18+y+30+2y+45 = 150 \implies 105+3y = 150\)
\(3y = 45; y = 15\)
Probability of 5 = \(\frac{2\times 15}{150} = \frac{1}{5}\)