\frac{7}{6}
\frac{7}{3}
\frac{14}{5}
\frac{14}{3}
Correct answer is A
3x^2 - 7x + 6 = 0
α + β = \frac{7}{3};
αβ = 2;
\frac{1}{α} + \frac{1}{β} = \frac{α +β}{αβ}
\frac{7}{3} ÷ 2
= \frac{7}{6}
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