A force (10i + 4j)N acts on a body of mass 2kg which is a...
A force (10i + 4j)N acts on a body of mass 2kg which is at rest. Find the velocity after 3 seconds.
(5i3+2j3)ms−1
(10i3+4j3)ms−1
(5i+2j)ms−1
(15i+6j)ms−1
Correct answer is D
Recall, F=mass×acceleration⟹acceleration=forcemass
= 10i+4j2=(5i+2j)ms−2
= v=u+at⟹vat 3 seconds=0+(5i+2j×3)
= (15i+6j)ms−1
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