x3−4x−9
x3−4x+9
x3+4x−9
x3+4x+9
Correct answer is A
dydx=3x2−4
y=∫(3x2−4)dx=x3−4x+c
y = 6 when x = 3
6=33−4(3)+c⟹6=27−12+c
c=6−15=−9
y=x3−4x−9
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