log \(\frac{2}{7}\)
log 2
log \(\frac{2}{9}\)
log 9
Correct answer is C
\(\frac{1}{3}\) log8 + \(\frac{1}{3}\) log 64 - 2 log6
= log 2 + log 4 - log 36
= log \(\frac{8}{36}\)
= log \(\frac{2}{9}\)
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