\(8\pi cm^{2}s^{-1}\)
\(16\pi cm^{2}s^{-1}\)
\(24\pi cm^{2}s^{-1}\)
\(48\pi cm^{2}s^{-1}\)
Correct answer is D
Surface area of sphere, \( A = 4\pi r^{2}\)
\(\frac{\mathrm d A}{\mathrm d r} = 8\pi r\)
The rate of change of radius with time \(\frac{\mathrm d r}{\mathrm d t} = 3cm s^{-1}\)
\(\frac{\mathrm d A}{\mathrm d t} = (\frac{\mathrm d A}{\mathrm d r})(\frac{\mathrm d r}{\mathrm d t})\)
= \(8\pi \times 2cm \times 3cm s^{-1} = 48\pi cm^{2}s^{-1}\)
If \(\log_{3} x = \log_{9} 3\), find the value of x....
Given that \(y = x(x + 1)^{2}\), calculate the maximum value of y....
Express \(\frac{3}{3 - √6}\) in the form \(x + m√y\)...
A particle is acted upon by forces F = (10N, 060º), P = (15N, 120º) and Q = (12N, 200º...
Simplify \(\frac{\sqrt{128}}{\sqrt{32} - 2\sqrt{2}}\)...
If \(8^{x} ÷ (\frac{1}{4})^{y} = 1\) and \(\log_{2}(x - 2y) = 1\), find the value of (x ...