xx+1
−1x+1
1−x(x+1)2
1(x+1)2
Correct answer is D
ddx(xx+1) = vdudx−udvdxv2
u = x, dudx = 1, v = x + 1, dvdx = 1
= (x+1)(1)−x(1)(x+1)2
= x+1−x(x+1)2
= 1(x+1)2
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