\(\frac{-y}{4x+y-3}\)
\(\frac{y}{4x+y-3}\)
\(\frac{-y}{4x+x-3}\)
\(\frac{y}{4x+x-3}\)
Correct answer is D
2y\(^2\) + 7 = 3y - xy, find \(\frac{dy}{dx}\)
4y \(\frac{dy}{dx}\) + 0 = 3 \(\frac{dy}{dx}\) - x \(\frac{dy}{dx}\) + y
{4x+x-3} \(\frac{dy}{dx}\) = y
= \(\frac{y}{4x+x-3}\)
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