-1
- \(\frac{1}{2}\)
\(\frac{1}{2}\)
1
Correct answer is D
Lim(\(\frac{1 - x}{x^2 - 3x + 2}\))
= \(^{lim}_{x \to 1} \begin{pmatrix} \frac{1 - x}{x^2 - 3x + 2} \end {pmatrix}\)
= \(^{lim}_{x \to 1} \begin{pmatrix} \frac{x - 1}{(x - 2)(x + 1)} \end {pmatrix}\)
= \(\frac{-1}{1 - 2}\)
= \(\frac{-1}{-1}\)
= 1