\(\frac{117}{125}\)
\(\frac{24}{25}\)
\(\frac{3}{5}\)
\(\frac{7}{25}\)
Correct answer is C
Cos (x + y)
= cos x cos y - sin x sin y
cos (x + y) = \(\frac{4}{5} \times \frac{24}{25} - \frac{3}{5} \times \frac{7}{25}\)
= \(\frac{96}{125} - \frac{21}{125} = \frac{96 - 21}{125}\)
= \(\frac{75}{125}\)
= \(\frac{3}{5}\)
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