4 + 8 + 16 + 32 + ...
\(\frac{1}{2}\) + 2 \(\frac{1}{2}\) + 12\(\frac{1}{2}\) + 62 \(\frac{1}{2}\) + ..
\(\frac{4}{81}\) + \(\frac{2}{27}\) + \(\frac{1}{9}\) + \(\frac{1}{6}\) + ...
128 + 64 + 32 + 16 + ...
Correct answer is D
No explanation has been provided for this answer.