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Solve log2(12x10)=1+log2(4x+3)...

Solve log2(12x10)=1+log2(4x+3)

A.

4.75

B.

4.00

C.

1.75

D.

1.00

Correct answer is B

log2(12x10)=1+log2(4x+3)

Recall, 1=log22, so

log2(12x10)=log22+log2(4x+3)

= log2(12x10)=log2(2(4x+3))

(12x10)=2(4x+3)

12x - 8x = 4x = 6 + 10 = 16 \implies x = 4