\(-\frac{1}{2}\)
\(\frac{1}{4}\)
\(\frac{1}{2}\)
\(1\)
Correct answer is B
The equation \(ax^{2} + bx + c\) is a perfect square if \(b^{2} = 4ac\).
\(x^{2} - x + p\)
\((-1)^{2} = 4(1)(p)\)
\(1 = 4p \implies p = \frac{1}{4}\)
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