−5x(1−x2)6
−10x(1−x2)6
5x(1−x2)6
10x(1−x2)6
Correct answer is D
y=1(1−x2)5=(1−x2)−5
Let u = 1−x2;y=u−5
dudx=−2x;dydu=−5u−6
Using chain rule:
dydx=dydu×dudx
dydx=−2x×−5u−6
dydx=−2x×−5(1−x2)−6
∴
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