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If \(\begin{vmatrix}  1+2x & -1 \\ 6 & 3-x \end...

If |1+2x163x|=3, find the values of x.

A.

x=3,2

B.

x=4,23

C.

x=4,32

D.

x=4,32

Correct answer is D

|1+2x163x|=3(1+2x)(3x)(6)=3

3x+6x2x2+6=3

2x2+5x+3+6+3=0

Multiplying through with -1, 

2x25x12=0

(2x+3)(x4)=0x=32,4