Given that M = \(\begin{pmatrix} 3 & 2 \\ -1 & 4 \end{pmatrix}\) and N = \(\begin{pmatrix} 5 & 6 \\ -2 & -3 \end{pmatrix}\), calculate (3M - 2N)

A.

\(\begin{pmatrix} 1 & 6 \\ 1 & 18 \end{pmatrix}\)

B.

\(\begin{pmatrix} -1 & -6 \\ 1 & 18 \end{pmatrix}\)

C.

\(\begin{pmatrix} 1 & 6 \\ -1 & -18 \end{pmatrix}\)

D.

\(\begin{pmatrix} -1 & -6 \\ -1 & -18 \end{pmatrix}\)

Correct answer is B

3M = 3 \(\begin{pmatrix} 3 & 2 \\ -1 & 4 \end{pmatrix}\)

 = \(\begin{pmatrix} 9 & 6 \\ -3 & 12 \end{pmatrix}\)

2N = 2 \(\begin{pmatrix} 5 & 6 \\ -2 & -3 \end{pmatrix}\) 

= \(\begin{pmatrix} 10 & 12 \\ -4 & -6 \end{pmatrix}\)

(3M - 2N) = \(\begin{pmatrix} 9 & 6 \\ -3 & 12 \end{pmatrix}\) - \(\begin{pmatrix} 10 & 12 \\ -4 & -6 \end{pmatrix}\)