\(\frac{27}{64}\)y\(^2\)
\(\frac{27}{8}\)y\(^2\)
8y\(^2\)
9y\(^2\)
Correct answer is B
(2x + \(\frac{3y}{4}\))\(^3\)
= 3(2x) (\(\frac{3y}{4}\))\(^2\)
= \(\frac{27}{8}\)y\(^2\)
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