{x: -1 ≤ x ≤ 3}
{x: -3 ≤ x ≤ 1}
{x: -3 ≤ x ≤ -1}
{x: 1 ≤ x ≤ 3}
Correct answer is A
Let x\(^2\) - 2x - 3 = 0;
(x+1)(x-3) = 0
The zeros of the function are x = -1 and 3
The solution set is { x: -1 ≤ x ≤ 3}
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