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A particle starts from rest and moves through a distance \(S...

A particle starts from rest and moves through a distance S=12t22t3 metres in time t seconds. Find its acceleration in 1 second.

A.

24ms2

B.

18ms2

C.

12ms2

D.

10ms2

Correct answer is C

ds(t)dt=v(t) and dv(t)dt=a(t)

\frac{\mathrm d (24t - 6t^{2})}{\mathrm d t} = 24 - 12t = a(t)

a(1) = 24 - 12(1) = 24 - 12 = 12ms^{-2}