2x2−9x+15=0
2x2−9x+13=0
2x2−9x−13=0
2x2−9x−15=0
Correct answer is B
Note: Given the sum of the roots and its product, we can get the equation using the formula:
x2−(α+β)x+(αβ)=0. This will be used later on in the course of our solution.
Given equation: 2x2−5x+6=0;a=2,b=−5,c=6.
α+β=−ba=−(−5)2=52
αβ=ca=62=3
Given the roots of the new equation as (α+1) and (β+1), their sum and product will be
(α+1)+(β+1)=α+β+2=52+2=92=−ba
(α+1)(β+1)=αβ+α+β+1=3+52+1=132=ca
The new equation is given by: x2−(−ba)x+(ca)=0
= x2−(92)x+132=2x2−9x+13=0
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