The probability that kebba, Ebou and Omar will hit a target are $\frac{2}{3}$ , $\frac{3}{4}$ and $\frac{4}{5}$ respectively. Find the probability that only Kebba will hit the target.

$\frac{2}{5}$

$\frac{7}{60}$

$\frac{1}{30}$

$\frac{1}{60}$

Correct answer is C

Hence the probability that only Kebba will hit the target

= P(K)xP(E')xP(O')

= $\frac{2}{3} \times \frac{1}{4} \times \frac{1}{5}$

= $\frac{1}{30}$

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