\(\frac{2}{5}\)
\(\frac{7}{60}\)
\(\frac{1}{30}\)
\(\frac{1}{60}\)
Correct answer is C
Hence the probability that only Kebba will hit the target
= P(K)xP(E')xP(O')
= \(\frac{2}{3} \times \frac{1}{4} \times \frac{1}{5}\)
= \(\frac{1}{30}\)