In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75o. Find the value of y
A.
105o
B.
110o
C.
130o
D.
150o
Correct answer is A
In \(\bigtriangleup\) PQR,
Q = S = 75o (Corresponding angle)
R = Q = 75o (Base angles of an isosceles \(\bigtriangleup\))
But, y + 75o = 180o (Sum of angles in a straight line)
y = 180 - 75
y = 105o