From the equation whose roots are x = \(\frac{1}{2}\) and -\(\frac{2}{3}\)

A.

6x2 - x + 2 = 0

B.

6x2 - x - 2 = 0

C.

6x2 + x + 2 = 0

D.

6x2 + x - 2 = 0

Correct answer is D

x = \(\frac{1}{2}\) and x = \(\frac{-2}{3}\)

expand (x - \(\frac{1}{2}\))(x + \(\frac{2}{3}\)) = 0

x(x + \(\frac{2}{3}\)) - \(\frac{1}{2}(x + \frac{2}{3}\)) = 0

x2 + \(\frac{4x - 3x}{6} - \frac{2}{6} = 0\)

\(x^2 + \frac{x}{6} - 2 = 0\)

6x2 + x - 2 = 0