Two beads are drawn at random, one after the other, with replacement, from a box containing 5 red and 7 white identical beads. What is the probability that the beads are the same colour
\(\frac{119}{144}\)
\(\frac{95}{144}\)
\(\frac{37}{72}\)
\(\frac{49}{144}\)
\(\frac{1}{6}\)
Correct answer is C
No explanation has been provided for this answer.