y = 160 + x
y = 100 + x
y = 160 - x
y = x - 100
Correct answer is C
Sum of the angles in a quadrilateral = 360o (x + 10o) + 2y + 90o + 100 - y = 360o x + y + 200 = 360o y = 360 - 200 - x y = 160 - x
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