The angles of a quadrilateral are (x + 10)^o, 2y^o, 90^o and (100 - y)^o, Find y in terms of x

A.

y = 160 + x

B.

y = 100 + x

C.

y = 160 - x

D.

y = x - 100

View answer & explanation

Correct answer is C

Sum of the angles in a quadrilateral = 360^o

(x + 10^o) + 2y + 90^o + 100 - y = 360^o

x + y + 200 = 360^o

y = 360 - 200 - x

y = 160 - x

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